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1. ⇒ (MHT CET 2023 11th May Evening Shift )

Calculate the degree of dissociation of $0.01 M$ acetic acid at $25^{\circ} C [Λ_{c} = 15.0 Ω^{- 1} {cm}^{2} {mol}^{- 1}$ and $Λ_{0} = 300 Ω^{- 1} {cm}^{2} {mol}^{- 1}]$

0.042

0.035

0.025

0.05

Correct Option is (D)

$Degree of dissociation (α) = \frac{Λ_{c}}{Λ_{0}} = \frac{15.0}{300} = 0.05$

⇒Ionic Equilibrium