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6. ⇒  (MHT CET 2023 9th May Evening Shift )

A solution of 8   g of certain organic compound in 2   dm 3 water develops osmotic pressure 0.6   atm at 300   K . Calculate the molar mass of compound. [R = 0.082 atm dm 3 K 1 mol 1 ]

A. 148   g   mol 1

B. 164   g   mol 1

C. 172   g   mol 1

D. 180   g   mol 1

Correct Option is (B)

π = W 2 RT M 2   V M 2 = W 2 RT π V M 2 = 8   g × 0.082 dm 3   atm   K 1   mol 1 × 300   K 0.6   atm × 2 dm 3 = 164   g   mol 1

7. ⇒  (MHT CET 2023 9th May Morning Shift )

0.2   M aqueous solution of glucose has osmotic pressure 4.9 atm at 300   K . What is the concentration of glucose if it has osmotic pressure 1.5   atm at same temperature?

A. 0.03   M

B. 0.04   M

C. 0.05   M

D. 0.06   M

Correct Option is (D)

π = M × R × T

M = π RT = 1.5 0.082 × 300 = 0.06   M

8. ⇒  (MHT CET 2021 20th September Morning Shift )

Which of the following solutions does not flow in either direction, when separated by semipermeable membrane? (Molar mass : glucose = 180, urea = 60)

A. 18 g urea dm 3 and 18 g glucose dm 3

B. 6 g urea dm 3 and 36 g glucose dm 3

C. 6 g urea dm 3 and 24 g glucose dm 3

D. 12 g urea dm 3 and 36 g glucose dm 3

Correct Option is (D)

n urea  = 12 60 = 0.2  and  n glucose  = 36 180 = 0.2

Now, n urea  = n glucose 

π urea  = π glucose 

Hence, if these solutions are separated by a semipermeable membrane, there is no flow of solvent in either direction.