The Correct Answer is Option (A)
Pentavalent
activities
have
excess
free
e
6. (JEE Main 2021 (Online) 26th August Morning Shift)
Statement
I
:
By
doping
silicon
semiconductor
with
pentavalent
material,
the
electrons
density
increases.
Statement
II
:
The
n-type
semiconductor
has
net
negative
charge.
In
the
light
of
the
above
statements,
choose
the
most
appropriate
answer
from
the
options
given
below
:
A. Statement - I is true but Statement - II is false.
B. Statement - I is false but Statement - II is true.
C. Both Statement I and Statement II are true.
D. Both Statement I and Statement II are false.
The Correct Answer is Option (A)
Pentavalent
activities
have
excess
free
e
7. (JEE Main 2021 (Online) 25th February Evening Shift)
For extrinsic semiconductors; when doping level is increased;
A. Fermi-level of both p-type and n-type semiconductors will go upward for T > TFK and downward for T < TFK, where TF is Fermi temperature.
B. Fermi-level of p-type semiconductor will go upward and Fermi-level of n-type semiconductors will go downward
C. Fermi-level of p and n-type semiconductors will not be affected.
D. Fermi-level of p-type semiconductors will go downward and Fermi-level of n-type semiconductor will go upward.
The Correct Answer is Option (D)
In
n-type
semiconductor
pentavalent
impurity
is
added.
Each
pentavalent
impurity
donates
a
free
electron.
So
the
Fermi-level
of
n-type
semiconductor
will
go
upward.
And
In
p-type
semiconductor
trivalent
impurity
is
added.
Each
trivalent
impurity
creates
a
hole
in
the
valence
band.
So
the
Fermi-level
of
p-type
semiconductor
will
go
downward.
8. (JEE Main 2019 (Online) 9th January Morning Slot)
Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an n-type semiconductor, the density of electrons is 1019 m3 and their mobility is 1.6 m2/(V.s) then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to :
A. m
B. 4m
C. 0.4 m
D. 0.2 m
The Correct Answer is Option (C)
For
semiconductor,
Conductivity,
=
ne
q
e
+
nh
q
h
given
that
semiconductor
is
n-type.
So
contribution
of
holes
is
ignored.
nh
q
h
=
0
=
ne
q
e
Resistivity,
=
=
=
=
=
0.4
m
9. (JEE Main 2017 (Online) 8th April Morning Slot)
What
is
the
conductivity
of
a
semiconductor
sale
having
electron
concentration
of
hole
concentration
of
electron
mobility
of
2.0
m2
V1
s-1
and
hole
mobility
of
0.01
m2
V1
s1
?
(Take
charge
of
electronas
1.6
10
19
c)
A. 1.68 (-m)1
B. 1.83 (-m)1
C. 0.59 (-m)1
D. 1.20 (-m)1
The Correct Answer is Option (A)
Conductivity
of
semiconductor,
=
e
=
1.6
1019
(5
1018
2
+
5
1019
0.01)
=
1.6
1.05
=
1.68
10. (JEE Main 2016 (Offline))
The temperature dependence of resistance of and undoped in the temperature range is best described by :
A. Linear increases for exponential decrease of
B. Linear decrease for linear decrease for
C. Linear increase for linear increase for
D. Linear increase for exponential increase for
The Correct Answer is Option (A)