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6. (JEE Main 2021 (Online) 26th August Morning Shift)

Statement I : By doping silicon semiconductor with pentavalent material, the electrons density increases.

Statement II : The n-type semiconductor has net negative charge.

In the light of the above statements, choose the most appropriate answer from the options given below :

A. Statement - I is true but Statement - II is false.

B. Statement - I is false but Statement - II is true.

C. Both Statement I and Statement II are true.

D. Both Statement I and Statement II are false.

The Correct Answer is Option (A)

Pentavalent activities have excess free e , so e density increases but overall semiconductor is neutral.

7. (JEE Main 2021 (Online) 25th February Evening Shift)

For extrinsic semiconductors; when doping level is increased;

A. Fermi-level of both p-type and n-type semiconductors will go upward for T > TFK and downward for T < TFK, where TF is Fermi temperature.

B. Fermi-level of p-type semiconductor will go upward and Fermi-level of n-type semiconductors will go downward

C. Fermi-level of p and n-type semiconductors will not be affected.

D. Fermi-level of p-type semiconductors will go downward and Fermi-level of n-type semiconductor will go upward.

The Correct Answer is Option (D)

In n-type semiconductor pentavalent impurity is added. Each pentavalent impurity donates a free electron. So the Fermi-level of n-type semiconductor will go upward.

And In p-type semiconductor trivalent impurity is added. Each trivalent impurity creates a hole in the valence band. So the Fermi-level of p-type semiconductor will go downward.

8. (JEE Main 2019 (Online) 9th January Morning Slot)

Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an n-type semiconductor, the density of electrons is 1019 m 3 and their mobility is 1.6 m2/(V.s) then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to :

A. 2 Ω m

B. 4 Ω m

C. 0.4 Ω m

D. 0.2 Ω m

The Correct Answer is Option (C)

For semiconductor,

Conductivity, σ = ne q μ e + nh q μ h

given that semiconductor is n-type. So contribution of holes is ignored.

   nh q μ h = 0

    σ = ne q μ e

Resistivity, ρ = 1 σ

= 1 n e q μ e

= 1 10 19 × 1.6 × 10 19 × 1.6

= 1 1.6 × 1.6

= 0.4 Ω m

9. (JEE Main 2017 (Online) 8th April Morning Slot)

What is the conductivity of a semiconductor sale having electron concentration of 5 × 10 18 m 3 , hole concentration of 5 × 10 19 m 3 , electron mobility of 2.0 m2 V 1 s-1 and hole mobility of 0.01 m2 V 1 s 1 ?

(Take charge of electronas 1.6 × 10 19 c)

A. 1.68 ( Ω -m) 1

B. 1.83 ( Ω -m) 1

C. 0.59 ( Ω -m) 1

D. 1.20 ( Ω -m) 1

The Correct Answer is Option (A)

Conductivity of semiconductor,

σ = e ( η e μ e + η μ h )

= 1.6 × 10 19 (5 × 1018 × 2 + 5 × 1019 × 0.01)

= 1.6 × 1.05

= 1.68

10. (JEE Main 2016 (Offline))

The temperature dependence of resistance of C u and undoped S i in the temperature range 300 400 K , is best described by :

A. Linear increases for C u , exponential decrease of S i .

B. Linear decrease for C u , linear decrease for S i

C. Linear increase for C u , linear increase for S i .

D. Linear increase for C u , exponential increase for S i

The Correct Answer is Option (A)

JEE Main 2016 (Offline) Physics - Semiconductor Question 186 English Explanation