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31.(JEE Main 2019 (Online) 9th January Morning Slot )

A copper wire is stretched to make it 0.5% longer. The percentage change in its electrical resistance if its volume remains unchanged is :

(A) 2.0 %

(B) 2.5 %

(C) 1.0 %

(D) 0.5 %

Correct answer is (C)

We know,

R = ρ l A

and Volume (V) = A l

   A = V l

    R = ρ l 2 v

    Δ R R = 2 Δ l l

=    2 × 0.5

= 1%

32.(JEE Main 2018 (Online) 16th April Morning Slot )

The percentage errors in quantities P, Q, R and S are 0.5%, 1%, 3% and 1.5% respectively in the measurement of a physical quantity A = P 3 Q 2 R S .

The maximum percentage error in the value of A will be :

(A) 6.0%

(B) 7.5%

(C) 8.5%

(D) 6.5%

Correct answer is (D)

Given,

A = P 3 Q 2 R S

Δ A A = 3 Δ P P + 2 Δ Q Q + 1 2 Δ R R + Δ S S

Maximum percentage error in the value of A is

Δ A A × 100 = 3 × 0.5 + 2 × 1 + 1 2 × 3 + 1 × 1.5

= 6.5 %

33.(JEE Main 2018 (Online) 16th April Morning Slot )

The relative uncertainly in the period of a satellite orbiting around the earth is 10-2. If the relative uncertainty in the radius of the orbit is negligible, the relative uncertainty in the mass of the earth is :

(A) 10 2

(B) 2 × 10 2

(C) 3 × 10 2

(D) 6 × 10 2

Correct answer is (B)

From kepler's law,

T = 2 π r 3 G M

T2 = 4 π 2 G M r 3

M = 4 π 2 G × r 3 T 2

Δ M M = 2 Δ T T + 3 Δ r r

as Δ r r 0

| Δ M M | = 2 Δ T T = 2 × 10 2

34.(JEE Main 2018 (Offline) )

The density of a material in the shape of a cube is determined by measuring three sides of the cube and its mass. If the relative errors in measuring the mass and length are respectively 1.5% and 1%, the maximum error in determining the density is:

(A) 6%

(B) 2.5%

(C) 3.5%

(D) 4.5%

Correct answer is (D)

Density of a material (d) = M L 3

Error in density, Δ d d = Δ M M + 3 Δ L L

Δ d d × 100 = Δ M M × 100 + 3 Δ L L × 100

Δ d d × 100 = 1.5 % + 3 ( 1 ) % = 4.5 %

35.(JEE Main 2018 (Online) 15th April Morning Slot )

The relative error in the determination of the surface area of sphere is α . Then the relative error in the determination of its volume is :

(A) 3 2 α

(B) 2 3 α

(C) 5 2 α

(D) α

Correct answer is (A)

Relative error in the surface are of the sphere,

Δ S S = 2 × Δ r r = (given)

Relative error in volume,

Δ V V = 3 × Δ r r

= 3 × 1 2 × Δ S S

= 3 2 ×

= 3 2