11. ⇒ (MHT CET 2021 20th September Morning Shift )
A conductivity cell shows resistance of 600 ohm. If conductivity of 0.01 M KCl is 0.0015 Ω − 1 cm − 1 , what is cell constant?
A. 0.60 cm − 1
B. 0.45 cm − 1
C. 0.90 cm − 1
D. 0.75 cm − 1
Correct Option is (C)
R = 600 Ω , k KCl = 0.0015 Ω − cm − 1 , c = 0.01 M Cell constant = k KCl × R solution = 0.0015 Ω − 1 cm − 1 × 600 Ω = 0.90 cm − 1