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1. ⇒  (MHT CET 2023 12th May Morning Shift )

If lattice enthalpy and hydration enthalpy of KCl are 699   kJ   mol − 1 and − 681.8   kJ   mol − 1 respectively. What is the enthalpy of solution of KCl ?

A. 8.20   kJ   mol − 1

B. 10.25   kJ   mol − 1

C. 13.80   kJ   mol − 1

D. 17.20   kJ   mol − 1

Correct Option is (D)

Δ soln  H = Δ L H + Δ hyd  H = + 699   kJ   mol − 1 + ( − 681.8   kJ   mol − 1 ) = 17.2   kJ   mol − 1

2. ⇒  (MHT CET 2023 9th May Evening Shift )

For NaCl ( s ) enthalpy of solution is 4   kJ   mol − 1 and lattice enthalpy is 790   kJ   mol − 1 . What is hydration enthalpy of NaCl ?

A. 786   kJ

B. 794   kJ

C. − 786   kJ

D. − 794   kJ

Correct Option is (C)

Δ soln  H = Δ L H + Δ hyd  H ∴ Δ hyd  H = Δ soln  H − Δ L H = 4   kJ   mol − 1 − 790   kJ   mol − 1 = − 786   kJ   mol − 1