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Topic 6 : Balancing of Redox Reactions Mole Based

1. Number of moles of MnO $_{4}^{-}$ required to oxidize one mole of ferrous oxalate completely in acidic medium will be ⇒ (AIPMT 2008)

A. 7.5 moles

B. 0.2 moles

C. 0.6 moles

D. 0.4 moles

The Correct Answer is Option (C)

The balanced ionic equation for oxidation of ferrous oxalate by MnO₄^– in acidic medium is as follows :

3MnO₄^- + 5FeC₂O₄ + 24H⁺ $\to$

3Mn²⁺ + 10CO₂ + 12H₂O + 5Fe³⁺

Thus, 5 moles of FeC₂O₄ require 3 moles of MnO₄^-.

So, 1 mole of FeC₂O₄ requires

= $\frac{3}{5}$ = 0.6 moles of MnO₄^-

⇒Redox

Topic 6 : Balancing of Redox Reactions Mole Based