⇒Derivative

Correct Option is (D)

$\begin{array}{rl}& \mathrm{y}=2\sin \mathrm{x}+3\cos \mathrm{x}\\ & \therefore \frac{\mathrm{dy}}{\mathrm{dx}}=2\cos \mathrm{x}-3\sin \mathrm{x}\\ & \therefore \frac{{\mathrm{d}}^2\mathrm{y}}{{\mathrm{dx}}^2}=-2\sin \mathrm{x}-3\cos \mathrm{x}=-(2\sin \mathrm{x}+3\cos \mathrm{x})=-\mathrm{y}\\ & \therefore \mathrm{y}+\frac{{\mathrm{d}}^2\mathrm{y}}{{\mathrm{dx}}^2}=0\\ & \text{ We have }\mathrm{y}+\mathrm{A}\frac{{\mathrm{d}}^2\mathrm{y}}{{\mathrm{dx}}^2}=B\Rightarrow \mathrm{A}=1,\mathrm{B}=0\end{array}$